year . profit interest . . . balance . . . . . . loan
0 . . . . . . . . . . . . . . . . . . . . . . . . 0
1 400,000 . . . . . . .. . . . 400,000
2 400,000 . . . . . .. . . -1,100,000 1,900,000
3 300,000 -110,000 . . -690,000
4 300,000 . -69,000 . . -321,000
5 300,000 . -32,100 . . . .11,100
6 300,000 . . . . .. . 0 . . . 311,100
7 300,000 . . . . .. . 0 . . . 611,100
Net ROI = 611,100/1,900,000 = 32.163%
Comparable compound interest rate = 5.7358%
This is NOT the IRR interest. To calculate that we need
V = (((P(1 + i)^2 - p(1 + i) - p)(1 + i) - p)(1 + i) - p)(1 + i) - p
V = ((P(1 + i)^3 - p(1 + i)^2 - p(1 + i) - p)(1 + i) - p)(1 + i) - p
V = (P(1 + i)^4 - p(1 + i)^3 - p(1 + i)^2 - p(1 + i) - p)(1 + i) - p
V = P(1 + i)^5 - p(1 + i)^4 - p(1 + i)^3 - p(1 + i)^2 - p(1 + i) - p
V = P(1 + i)^5 - p((1 + i)^4 + (1 + i)^3 + (1 + i)^2 + (1 + i) + 1)
V = P(1 + i)^5 - (p/i)(1 + i)^5
V = (1 + i)^5(P - (p/i))
V/(1 + i)^5 - P = -p/i
i = -p/(V/(1 + i)^5 - P), which must be iterated to find IRR
i = 300,000/(611,100/(1 + i)^5 + 1,900,000),
i = 1.533246%
Note that this IRR incorporates the 10% interest paid out on the loan.
At the end of 2 years, the city would have a balance of $800,000. After the 7 year program, the city would have a balance of $611,100. Each successive iteration would require borrowing an additional $188,900. If year 3 income is $400,000 instead of $300,000, the payout and IRR are much better.
Based on the increasing cost of supporting the program, I would recommend against it.
2007-03-26 23:27:29
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answer #1
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answered by Helmut 7
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