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If a wet steam of certain dryness fraction and at certain pressure, is taken in a cylindrical container, then what time is required to settle the water particles in the steam(by gravity). Please answer this question, its urgent for me.

2007-03-25 00:28:55 · 1 answers · asked by chirag m 1 in Science & Mathematics Engineering

1 answers

Normally oil/water separators are designed such that the residence time is sufficient for a very small droplet to rise from the bottom of the vessel at the inlet end to coalesce at the surface at the outlet end. It is of course an idealised scenario due to currents within the vessel but works OK in pratice. The time required will depend on the length/diameter ratio of the pressure vessel (long thin ones being better but less economic to construct). Stokes Law applies to calculating the velocity at which the water droplet rises and the density and viscosity of the oil are parameters one needs to know. I can't remember the critical droplet size I used to use years ago but the below reference mentions 150 micron. http://www.oil-water-separator.net/separators-coalescing-theory.html

2007-03-25 05:31:38 · answer #1 · answered by Robert A 5 · 0 0

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