Math question (pre calculus)?

Question

y = ((sqrt of x) - 2) (3(sqrt of x) + 8) at P (4, 0)

Find the equation of the tangent.
I got 3x-16y-12=0 but this is wrong according to book. if possible show me the steps thannks

Answer 1

Try this: 3x + 8(sqrt of X) - 6(sqrt of x) -16 =
3x + 2(sqrt of x) - 16 =
12 + 4 - 16 = 0

So when x=4, y=0

It all breaks down to x = y+4