2007-02-24 07:05:00 · 7 answers · asked by ejump17 2 in Science & Mathematics ➔ Engineering
This one's right up my alley!
Watts = Volts x Amps (The definition of electrical energy.)
Use algebra to rearrange the equation.
Amps = Watts / Volts
Amps = 100 W / 120 V = 0.8333...A
6 Amp / 0.833 A = 7.2 Lights
Having done the math, there's a few other details to worry about. The type of fuse you're using matters very much. Tungsten lamps draw more than their rated current until they come up to temperature. This means, if you use a fast-blow fuse such as a 3AG or AGC type, it may blow the instant the circuit is energized. I suggest a slow blow type. It'll have a little coil spring inside the glass tube. This way the lamps will get up to temperature before the fuse blows.
Also, 18 AWG is the minimum wire gauge for a 6 amp circuit. If the round trip (ie., both ways) wire run totals more that 25 feed or so, it's prudent to use at least 16 AWG wire. Don't burn your house down 'cause you're too cheap or too ignorant to use the proper gauge. You WANT that fuse to blow before the wire catches fire. Right?
2007-02-24 07:38:00 · answer #1 · answered by Diogenes 7 · 0⤊ 0⤋
that depends on the voltage. say you have 100 Volts ( and also the lamp is for 100 Volts )
in that case a lamp of 100 W concumes 100W/100Volt = 1 Ampere
so then you can connect 6 such lamps but i would go for a little bit less just to be sure, you wont want that your power unit explode ( although it might give you aa magnificant view , but if yyou want to see explosions , there are better ways to do so dont I say ) good luck , may my input enlighten you.
2007-02-24 16:03:35 · answer #2 · answered by gjmb1960 7 · 0⤊ 0⤋
If you have 110v * 6 amp = 660 watt, you can connect 6 lights 100 watt, and one of 60 watt.
2007-02-24 18:57:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Typical engineers...they over complicate the ansewer and are still wrong.......the lowest amperage A/C fuse permitted for household use by the NEC is 15 amps
2007-02-24 21:06:33 · answer #4 · answered by dd964vet 2 · 0⤊ 0⤋
At 120 volts, each bulb would consume 0.83 Amps.
It would support 7 bulbs.
At 220 volts, each bulb would consume 0.45 Amps.
It would support 13 bulbs.
(P=IE where P=watts, I=Amps and E=voltage)
2007-02-24 15:25:17 · answer #5 · answered by LeAnne 7 · 0⤊ 0⤋
Amps time the voltage will = the watts.
2007-02-24 15:19:38 · answer #6 · answered by JOHNNIE B 7 · 0⤊ 0⤋
watt/volts = amps
100w / 120v = .83amp draw per light
6 would be safe, 7 would be pushing the limits
2007-02-24 15:20:14 · answer #7 · answered by corqmaker 2 · 0⤊ 0⤋