English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

3 MEN GO INTO A MOTEL. THE MAN BEHIND THE DESK SAID THE ROOM IS $30

>>

>> SO EACH MAN PAID $10 AND WENT TO THE ROOM.

>>

>> A WHILE LATER THE MAN BEHIND THE DESK REALIZED THE ROOM WAS ONLY $25

>>

>> SO HE SENT THE BELLBOY TO THE 3 GUYS' ROOM WITH $5.

>>

>> ON THE WAY THE BELLBOY COULDN'T FIGURE OUT HOW TO SPLIT $5 EVENLY

>> BETWEEN 3 MEN, SO HE GAVE EACH MAN A $1 AND KEPT THE OTHER $2 FOR

>> HIMSELF.

>>

>> THIS MEANT THAT THE 3 MEN EACH PAID $9 FOR THE ROOM, WHICH IS A TOTAL OF

>> $27, ADD THE $2 THAT THE BELLBOY KEPT = $29.

>>

>> WHERE IS THE OTHER DOLLAR?

2007-01-15 02:57:28 · 16 answers · asked by sdilib 1 in Entertainment & Music Jokes & Riddles

16 answers

You misdid the addition. Please let me explain.

The three men did each pay $9 for the room, but that includes what the bellboy kept. The other $3 were given to the men, $1 each.

$9*3+$1*3=$30

2007-01-15 03:00:54 · answer #1 · answered by er_i_m 4 · 0 1

The riddle is just not worded 'properly'.
If you have the $30, return $3. then the Bellboy had kept $2. you are not adding the $2 but rather subtracting it.
Therefore, as each (3) paid $9 = $27.
Minus the $2 that the Bellboy kept = $25.

2007-01-15 03:35:36 · answer #2 · answered by prizefyter 5 · 0 0

They each paid $10 and got back $1, so they each paid $9.

9 x 3 = 27

so they paid a total of $27.
Then you're not supposed to add the other $2, you subtract it. $3 of the 30 was given back, so that's subtracted, and $2 was kept by the bellboy, so you subract that also.

27 - 2 = 25

Which is what they were supposed to pay.

2007-01-15 03:23:09 · answer #3 · answered by me 2 · 0 0

Since the bellboy kept 2
Each man supposedly paid 25/3 +1 (returned) = 25/3 + 3/3 = 28/3
Therefore all three men supposedly paid 28/3 X3 = 28
3 was subsequently returned to the three 1X3=3
28-3=25 which is the room rent
QED

2007-01-15 03:08:34 · answer #4 · answered by Kool-kat 4 · 0 0

Look at it like this:
3 men each get a dollar 3x$1=$3
1 bellboy got 2 dollars 1x$2=$2
$3 + $2= $5.00

2007-01-15 03:04:58 · answer #5 · answered by nicole_g20 2 · 0 0

Yep the first guy was right. You can't add it up the way it was stated in the riddle. Each man paid $9, for a total of $27; if you add the $3 they got back, that adds up to $30, what they originally paid.

2007-01-15 03:31:11 · answer #6 · answered by kayjaykay 2 · 0 0

NO that easy u said each had to pay 9 dollars but if the guy gave the three back all together they wouldv'e paid 28 and i no 28 divide by 3 is't 9 and the that dude tooks the 2 dollars

2007-01-15 03:03:55 · answer #7 · answered by Anonymous · 0 0

The men get $5 in change. $5 divided 3 ways gives $1.67 per person. Each man acually paid $8.33 per person for the room. $8.33 X 3 = $25. $25 plus the $5 change, no matter how it is split, equals $30.

2007-01-15 03:06:50 · answer #8 · answered by furball17 2 · 0 0

omg!!!!! i had this b4!!! only it was a hotel, lol. anyways, $35 was the total (including the money they got back.) subtracting the $2 the bellman kept dividing that buy 3= $11 paid by each person.

2007-01-15 03:11:16 · answer #9 · answered by <3 5 · 0 0

30for room - 2 dollars to thief
=28 dollars
$28divided by 3 men=9.33 each (actual cost of room)

2007-01-15 03:11:19 · answer #10 · answered by high 1 · 0 0

fedest.com, questions and answers