its not possible to determine without knwoing the dimensions of the tank,since the flow rate of the water that is going out depends on the water head level.
i.e. if the tank is tall with smaler cross section area (say 0.25m length by 0.25m breadth by 16m high) , water will flow out faster than that of a less taller tank with big cross sectional area (0.5 m length, 0.5m breadth by 4 m high). Both of the tanks have the same capacity but the taller tank would discharge more water than the shorter tank for a given period of time.
2006-12-30 17:56:19
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answer #1
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answered by vEnKat 3
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It's gonna matter how deep the water is, isn't it? If the tank is tall the weight will be integrated from zero depth to water level and have more pressure than a tank that so so big the water is say, 1/2 inch deep. I think it's a matter referred to as 'head' pressure. I haven't done a problem like this in a long time - I'm not positive.
2006-12-31 01:58:57
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answer #2
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answered by Anonymous
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You have to integrate the equation, and to do that you have to know the geometrics involved not only of the tank, but also the kind of oriface or outlet device involved.
The basic equation for the velocity, v, of flow for a fluid under pressure is v = (2 g h)^2. Thus you can see that velocity is a function of the height of the fluid.
Q, or the flow rate, = v A, where A is the area of the oriface. Since the rate varies with time, that means you have to integrate with respect to time.
2007-01-01 23:00:26
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answer #3
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answered by daedgewood 4
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An unlimited factors could come into play.
1. Do you REALLY want to open the Valve?
2. What is in the Tank?
3. Is your sisters name written on the tank in spraypaint.
4. Does your dad own the tank?
5. Where is the flow going???!!!
And many many more.... Anyone care to help out?
2006-12-31 01:17:10
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answer #4
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answered by Jack Tax 3
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About 3 hours I would guess.
2006-12-31 01:15:58
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answer #5
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answered by Aussies-Online 5
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i pour gasoline on myself and play with matches
2006-12-31 01:14:26
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answer #6
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answered by sir confused 1
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