Does the prospective bride or groom buy the man's ring?
2006-12-30 14:42:41 · 13 answers · asked by wayde_york 1 in Family & Relationships ➔ Weddings
Usually the bride.
2006-12-30 14:47:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Either the bride and groom could buy the ring. The only thing is that if the bride is buying the ring the groom has to go with you to chose ring.
2007-01-03 03:37:31 · answer #2 · answered by thirisa 1 · 0⤊ 0⤋
Traditionally the bride chooses the ring and has it engraved with a message without the groom finding out. However if you are even the slightest bit worried about what you'll be wearing for the rest of your life... I suggest you both go shopping.... or you'll spend a lifetime regretting it. She can still choose the inscription on her own ;)
As for the financial aspect... it used to be the bride. Now it all depends on the budget agreed to when you started planing. If you haven't done the budget yet....start now! There are lots of Internet helps out there.
2006-12-30 15:13:01 · answer #3 · answered by emf 1 · 2⤊ 0⤋
The prospective bride.
2006-12-30 14:57:26 · answer #4 · answered by jeepy1999 2 · 0⤊ 0⤋
Tradition says the bride does. Sometimes couples are buying theirs in sets these days so the couple together pays for it.
2006-12-30 17:34:55 · answer #5 · answered by steffiegirl815 3 · 0⤊ 0⤋
The bride.
2006-12-30 16:17:06 · answer #6 · answered by Santa's Elf 4 · 0⤊ 0⤋
usually the bride, but it depends on the situation. Many couples are already living together and sharing expenses, and so who pays really is irrelavent.
2006-12-30 18:05:55 · answer #7 · answered by Chrys 4 · 1⤊ 0⤋
the bride
2006-12-30 14:50:14 · answer #8 · answered by singledad 7 · 0⤊ 0⤋
The bride to be.
2006-12-30 14:50:12 · answer #9 · answered by robert m 7 · 0⤊ 0⤋
"Tradition" says the bride does. However, you both can go pick one out that you both like and get it together, or he can get it.. whatever your situation is just go with it. Best of wishes to you both.
2006-12-31 02:40:23 · answer #10 · answered by ? 3 · 0⤊ 0⤋