2006-12-30 13:15:38 · 16 answers · asked by Sadiq O 1 in Cars & Transportation ➔ Insurance & Registration
DUH! Yes, of course you are! Why would you possibly not be??
2006-12-30 19:58:38 · answer #1 · answered by Bostonian In MO 7 · 0⤊ 0⤋
If this was an unbroken chain of events then yes, you are responsible for all damages as a result of your hitting that first parked car.
2006-12-31 09:17:08 · answer #2 · answered by Chris 5 · 1⤊ 0⤋
Unfortunately yes. The direct cause of the second hit was due to your cars impact. So you would be repsonsible for those damages as well.
2006-12-30 13:28:08 · answer #3 · answered by Cysteine 6 · 0⤊ 0⤋
Legally, you may get out of being liable for the damage to the second car if you can prove that the cause of the second car's damage was due to the first car's driver's negligence in not applying the parking brake. You can perhaps try to argue that before the police make their report.
2006-12-30 13:26:23 · answer #4 · answered by Mickey 1 · 0⤊ 3⤋
Simply, yes, because you caused one car to hit another.
2006-12-30 13:18:14 · answer #5 · answered by zara01 4 · 1⤊ 0⤋
yes,you would be held responsible for it,,they would say since it was your accident that set off this chain of events,,that caused all of this,they would hold you responsible for all of it,the laws concerning accidents are kind of weird in certain ways,they can go for you sometimes or against you,,my luck they always go against me,,good luck hope this help,s.,,happy new years.
2006-12-30 13:25:44 · answer #6 · answered by dodge man 7 · 1⤊ 0⤋
yes as long at it was parked and no one in it
2006-12-31 13:21:20 · answer #7 · answered by jerry 7 · 1⤊ 0⤋
yes
2006-12-30 15:39:28 · answer #8 · answered by Dotr 5 · 0⤊ 0⤋
yes you are as you are the one that started the crash.
2006-12-30 13:18:15 · answer #9 · answered by mister ss 7 · 1⤊ 0⤋
Of course. You caused it to happen.
2006-12-30 13:19:35 · answer #10 · answered by oklatom 7 · 0⤊ 0⤋
yep because you caused the accident.
2006-12-30 13:24:26 · answer #11 · answered by Texas T 6 · 0⤊ 0⤋