2006-12-18 07:50:07 · 11 answers · asked by m and m 1 in Health ➔ Diseases & Conditions ➔ STDs
The friction from the two latex materials rubbing together can cause them to tear. You're better off using one.
2006-12-18 07:57:05 · answer #1 · answered by ☆skyblue 7 · 4⤊ 0⤋
Condoms are ninety 9% affective. birth control pills are (usually) ninety 9% affective. Use them at the same time, and also you're like an commercial for secure sex! Doubling up on condoms may reason breaks, because they rub up antagonistic to one yet another.
2016-11-30 22:30:40 · answer #2 · answered by cottom 4 · 0⤊ 0⤋
No because you will most likely cause the condoms to tear and that would defeat the purpose. I recommend buying a condom with spermicidal lubricant if you are concerned that much.
2006-12-18 14:26:29 · answer #3 · answered by Cute But Evil 5 · 1⤊ 0⤋
By wearing 2, one can slide off and make the other slide off causing a unexpected accident
2006-12-18 12:14:59 · answer #4 · answered by Justin 6 · 0⤊ 0⤋
You can't
It is safer to wear one condom. By wearing two, there is a higher risk of an accident
2006-12-18 07:52:42 · answer #5 · answered by Atreides1998 3 · 3⤊ 0⤋
wearing two condoms is not practicing safer sex... wearing two condoms causes them to wear down and to develop tears.....
stick with one.....
preferrably with spermicide....
2006-12-18 08:56:28 · answer #6 · answered by myheartisjames 5 · 2⤊ 0⤋
I believe 2 are safer then one, it all has to do with quantity of the ***, rather then the quality
2006-12-18 09:48:13 · answer #7 · answered by Anonymous · 0⤊ 1⤋
you can wear double or triple but whenever you see your dick going black, this is the time to stop.it will also be a safe sex of course.
2006-12-18 08:20:06 · answer #8 · answered by mukyon1 3 · 0⤊ 1⤋
Absolutely. Some men who have trouble lasting very long do this regularly.
2006-12-18 07:52:53 · answer #9 · answered by Phoenix, Wise Guru 7 · 0⤊ 3⤋
yes if he has a little thing,he might be able to get 3,4or5 on lol
2006-12-18 09:22:46 · answer #10 · answered by MRS.K 2 · 0⤊ 1⤋