Xc = _1_
piefC
Capacitive Reactance (Xc) in Ohms
Frequency (f) in Hz
Capacitance (C) in Farads in a electrical circuit
Taking 2pie as equal to 6.284
a) how i make 'f' the subject?
b) how do i calculate f when Xc = 318.47 Ohms, C = 1uF (equivalent to 1x10exp-6F)
im really stuck :(
2006-12-01 13:05:09 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
What do you mean by taking f as subject?
Its a simple substitution problem you are given with Xc, C and you know the constants substitute and get the answer.
f= 1/ 2*p*iXc*C
= 1/2*3.14*318.47*1uF
= 500 Hz
2006-12-01 13:21:50 · answer #1 · answered by Ramanadhan C 2 · 0⤊ 0⤋
What do you mean make "f" the "subject"? Is it find f in terms of C? that you get from Xc = 1/(2ÏfC): f = 1/(2ÏXcC); For part b, just put in the values for Xc and C into that equation.
2006-12-01 13:10:47 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
Snuffaluffagus.
2006-12-01 13:06:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
resonant frequency
2006-12-01 20:47:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋