A girl that is sensual, had a bright side and has a good efficient career. A pretty average body, but has a pretty face and can take care of herself.
Or an average looker that has a GREAT body, and can make money, just not at a reasonable rate?
2006-11-23 07:57:32 · 9 answers · asked by Anonymous in Family & Relationships ➔ Singles & Dating
The average looker can't really take care of herself and will depend on you. But, she has normal features, she's not ugly.
2006-11-23 08:05:05 · update #1
Either as long as they had a good personality and disposition.
2006-11-23 08:00:21 · answer #1 · answered by crazylegs 7 · 0⤊ 0⤋
The former. I've dated girls that were so dependant on me that they refused to order pizza! Anyone that can take care of themself is a winner in my book. Nothing wrong with the latter girl, you just didn't state that she could look after herself also. If she can, then I choose both.
2006-11-23 16:00:40 · answer #2 · answered by tipper 4 · 0⤊ 0⤋
how can she be an average looker with a great body? a hideous face?
2006-11-23 16:01:33 · answer #3 · answered by sufferingnomad 5 · 0⤊ 0⤋
The first one,who has a bright side.For she we both can make money.I can improve her abilities as long as she is having a bright side.
2006-11-23 16:04:37 · answer #4 · answered by mazen m 1 · 0⤊ 0⤋
I'll take the one with the great body...I don't care how much money she makes.
2006-11-23 16:02:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I'll take the average girl any day. Being with a hooker is nothing to "Clap" about.
2006-11-23 16:03:48 · answer #6 · answered by sluggo1947 4 · 0⤊ 0⤋
Who screws better. Plus it sounds like you already made up your mind with the career gal
2006-11-23 16:01:28 · answer #7 · answered by neilmccalister 3 · 0⤊ 0⤋
Give me the first one. Because when times get hard I know she has my best interest. And looks aren't everything it's what inside that counts.
2006-11-23 16:06:46 · answer #8 · answered by Anonymous · 0⤊ 0⤋
first one....I guess.
2006-11-23 16:02:20 · answer #9 · answered by Anonymous · 0⤊ 0⤋