2006-11-19 06:23:58 · 8 answers · asked by shaun w 1 in Science & Mathematics ➔ Engineering
As part of electrostatics: The difference of the electrostatic potential at two different points.
As part of electrodynamics: The voltage in electronic circuitry can be defined as electrostatic voltage (potential difference at two points of the circuit) changing through the time, but at exact moment having only one unchanging (static) value.
2006-11-19 06:27:43 · answer #1 · answered by Dimitar Hanrov 2 · 0⤊ 0⤋
Voltage is the difference in potential energy between two points due to the force of electrostatic attraction/repulsion. It indicates the ability of an electric field to produce a current.
2006-11-19 19:03:22 · answer #2 · answered by cedsinsane 1 · 0⤊ 0⤋
Voltage should be more correctly called "potential difference". It is actually the electron moving force in electricity (emf) and the potential difference is responsible for the pushing and pulling of electrons or electric current through a circuit.
2006-11-19 14:26:11 · answer #3 · answered by richard_beckham2001 7 · 1⤊ 0⤋
Voltage is defined as the product of current (I) with Resistance (R)
V = I x R
2006-11-20 14:33:21 · answer #4 · answered by C.B 1 · 0⤊ 0⤋
It's actualy the potential too move in electrical systems. that means one coloumb releases or absorbs energy by moving between two points with different voltage. it can be compared with pressure in mechanics of fluids , it is actualy the characteristic of a point in a space and not a physical substance.
so it is actually a difference between two ponts in space and shows how much electrical energy is released or absorbed by a substance by moving between these points.
2006-11-19 14:36:56 · answer #5 · answered by Armin G 1 · 0⤊ 0⤋
in relation to water, voltage would be the pressure required to push the flow (amperage/current) through the pipe (conductor/ohm/resistance)
2006-11-21 10:08:47 · answer #6 · answered by noodle_212 2 · 1⤊ 0⤋
The energy in a coulomb of charge.
2006-11-19 14:25:59 · answer #7 · answered by jacinablackbox 4 · 0⤊ 1⤋
I agree with Richard_b's answer.
2006-11-19 17:22:07 · answer #8 · answered by ddntruong 2 · 0⤊ 0⤋