solve the inequality 7+x<10 pleeeze help me?

Question

2. solve -8x < 2.
3. what is the sum of the first 10 positive integers?
4. solve the following equation 6/11 =114/n
5. solve y= log down 3 243.
6. solve log down 2 8 + 32
7. solve log down 6 60-log down 6 30.
8. solve the following equation for x: 64 = 2^3x

Answer 1

For #4, you should cross multiply: 6(n) = 11(114)
6n = 1254
n = 209

I don't understand what "log down" means.

Answer 2

especially situations that is way less complicated to handle those 2 sided inequalities as 2 inequalities. consequently we've: (a million) 7 > a million - 2x => 2x > a million - 7 => 2x > - 6 => x > -6/2 => x > -3 => -3 < x (2) a million - 2x -2x -2x x >/= 9/-2 notice we've divided by ability of a damaging extensive type and we could opposite the inequality => x >/= - 9/2 So we've: (a million) -3 < x and (2) x >/= - 9/2 the answer has to fulfill the two inequalities, consequently -3 < x >/= -9/2 With slightly bit journey those could be performed mutually: 7 > a million - 2x 6 > -2x 6/-2 < x >/= 9/-2 => -3 < x >/- 9/2

Answer 3

x<3
x>-1/4

10*11/2=55

6n=11*114 n=19*11=209

log_3 3^5=5.1=5

3log2 / (5log2)=3/5

log60/log6-log30/log6=1+log10/log6-1-log5/log6=log2/log6

(2^x)^3=4^3 2^x=2^2 x=+-2

Answer 4

for the 4th question;

6/11=114/n
=>6n=11*114
=>6n=1254--------->>>>n=1254/6
=>n=209.

Answer 5

your question is miscategorized. you may be a homeschool student, but you should categorize your question based on what you are asking, not who you are or what you do.
It was so nice of YA to give homework help it's very own section. You should use it.

Answer 6

subtract 7 from both sides, so x<3
that's the solution
now do your own homework