2006-09-25 09:31:15 · 6 answers · asked by kalie w 1 in Education & Reference ➔ Other - Education
x=6
y=2
First solve the first equation for y, to do so you subtract x from both sides so you are left with:
y=8-x
Next you plug in y=8-x for the y in the second problem so you have:
x-3(8-x)=0
Distribute the -3
x-24+3x=0
add 24 to both sides
x+3x=24
add the x's
4x=24
divide by 4 and you find that x=6
Next you plug in x=6 into one of the equations and solve for y.
6+y=8
subtract 6 from both sides
y=2
2006-09-25 09:35:20 · answer #1 · answered by oJmHo 2 · 0⤊ 0⤋
equation 1 = x+y =8 ------- y = 8 - x
equation 2= 2 = x-3y=0
it just rearranged the equation hope you understand
put equation 1 into equation 2like this *( this method is called Substitution )
x- 3(8-x) = 0
x- 24 +3x =0
-2x =24 + 0 - take like terms
4x =24
x= 6
there if x= 6 then put in into equation1
which is
x + y=8 or y = 8-x
y = 8 - 6
y= 2
there fore the solution to the question is x= 6 and y = 2
you can check by pluging it into the equation .
2006-09-25 09:42:10 · answer #2 · answered by cmd 2 · 0⤊ 0⤋
x=6 and y=2
2006-09-25 09:33:42 · answer #3 · answered by JoiseyFlyboy 2 · 0⤊ 0⤋
From the second equation: x = 3y
Plug that into the first equation:
3y + y = 8
4y = 8
y = 2
... and since x=3y, x=6.
Answer: x=6, y=2.
2006-09-25 09:34:28 · answer #4 · answered by Bramblyspam 7 · 0⤊ 0⤋
substitute x = 8 - y into the second equation
8 - y - 3y = 0
8 - 4y = 0
4y = 8
y = 2
then substitute y to find x
x + 2 = 8
x = 6
2006-09-25 09:34:12 · answer #5 · answered by JuJu 3 · 0⤊ 0⤋
x+y = 8
x -3y = 0
therefore
x = 3y
so replace x in the original equation with 3y
3y + y = 8
in other words
4 y = 8
y = 2
x = 6
2006-09-25 09:36:20 · answer #6 · answered by Rob 1 · 0⤊ 0⤋