2006-09-11 13:16:44 · 5 answers · asked by Queen G 1 in Education & Reference ➔ Home Schooling
= 3(x^2-2x+3)
so 3 is one factor, (x^2-2x+3) is another
2006-09-11 13:24:35 · answer #1 · answered by Judy 7 · 0⤊ 0⤋
3x^2 - 6x +9 = 3 (x^2 - 2x +3)
= 3(x^2-3x+x-3)
= 3((x (x-3) +1(x-3))
=3(x-3)(x+1)
All three are factors.
2006-09-11 23:49:39 · answer #2 · answered by jazideol 3 · 0⤊ 0⤋
The only factors are 3 and x^2-2x+3
You can't factor the second factor any further. Your only options would be (x+1)(x+3) which give you a middle term of +4x (not -2x), or (x-1)(x-3) which give you a middle term of -4x (again, not -2x). And if you use (x-3)(x+1), the last term is -3, not +3.
So 3(x^2-2x+3) is completely factored.
2006-09-12 02:06:08 · answer #3 · answered by homeschoolmom 5 · 0⤊ 1⤋
=3(x^2-2x+3)=3(x^2-3x+x-3)=3(x(x-3)+(x-3))=3(x-3)(x+1)
2006-09-11 22:29:47 · answer #4 · answered by ioana v 3 · 0⤊ 0⤋
try homework help if you don't understand your assignments
2006-09-11 14:08:57 · answer #5 · answered by Terri 6 · 0⤊ 0⤋