2006-09-06 08:53:39 · 7 answers · asked by lesia s 1 in Health ➔ Diseases & Conditions ➔ Heart Diseases
There are different types, a lot of people have what is called a functional heart murmur which means nothing serious just a innocent glitch in their heart, but the other type needs surgery or it can be very serious.
2006-09-06 08:57:14 · answer #1 · answered by sweet smile 3 · 3⤊ 0⤋
A murmur is a term used for an abnormal sound heard when your doctor/provider listens to your heart with a stethoscope. This murmur could be due to one of several different causes that vary from completely benign to very serious. The significance of a murmur can very easily be determined by a simple, non-invasive test called echocardiogram. You can learn more about echocardiogram at
http://drchander.com/echo.html
I hope this helps.
2006-09-06 23:14:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
To answer your question is yes. There are different types of murmers, some are no big deal, some are a big deal. The murmer is simply the turbulant blood flow caused by some pathology of the heart. The best thing is certainly be evaluated to determine the cause and treatment if any. An echocardiogram is non-evasive and can tell a lot about the health of heart valves.
2006-09-06 18:12:06 · answer #3 · answered by mr.answerman 6 · 1⤊ 0⤋
No, not as such. Many people go on to live long lives with heart murmurs.
However, a murmur might indicate some other problem.
2006-09-06 20:53:07 · answer #4 · answered by Tigger 7 · 0⤊ 0⤋
It depends on the type of murmur. See a cardiologist and have an echocardiogramme done.
2006-09-06 16:07:44 · answer #5 · answered by Developer 1 · 1⤊ 0⤋
Get it checked out! I did and found that I had to have my aortic valve replaced it is best to find out early it might be nothing but it also could be something get it checked out so you will know.
2006-09-07 02:51:24 · answer #6 · answered by Christopher W 2 · 0⤊ 0⤋
only if the noise is very, very loud..
couldn't help it.
2006-09-06 16:03:28 · answer #7 · answered by javila 1 · 0⤊ 2⤋