Well zero degrees celsius is 273 K, so half as cold as that is actually just 136.5 K, or -136.5 degrees C.
Kelvin (K) is the absolute measure of temperature.
2006-08-14 16:12:42
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answer #1
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answered by Anonymous
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Well, that's an interesting question. The first answer to pop into my head really didn't make much sense: ZERO - because, obviously, 2 x 0 = 0. But that would mean if the next day was 4 times colder, it would still be zero - and that doesn't make much sense either. So let's make sense - instead of zero C, we'll call it 32 degrees F - now the next day is 16 degrees F and that can be converted to C and with that, we can all live happily ever after.
2006-08-14 16:22:23
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answer #2
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answered by LeAnne 7
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-10 degrees. To me, -10 F feels twice as cold as 0 F.
2006-08-14 18:05:42
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answer #3
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answered by Lee J 4
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Like the first answer says, all you have to do is convert the 0* from whatever temperature unit it is currently in to degrees Kelvin, since it is the only absolute temperature scale (where 0 degrees is absolute zero). Once the the temperature is in Kelvin you can simply divide the number by two to find the answer.
2006-08-14 16:33:44
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answer #4
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answered by dan81_dr 1
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-1 or -2
2006-08-14 16:12:56
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answer #5
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answered by vener a 2
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O* centigrade =32*f therefore twice as cold is 16*f which is minus 8.89*c (thats assuming youre talking centigrade)
Minus 8-89*c =264k
2006-08-14 22:56:00
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answer #6
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answered by bryte 3
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The problem is incomplete. We don't know the starting point to measure the temperature drop down to zero. If the norm is 70 and today it's 0, tomorrow is going to be -70.
2006-08-14 16:14:26
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answer #7
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answered by Dave 5
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As stated from the first person who responded:
-136.5 C translates to -213.7 degrees Fahrenheit
That's cold!
2006-08-14 16:18:58
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answer #8
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answered by Anonymous
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The answers in which they tell you to convert to the Kelvin scale are the correct answers and for the reason stated.
2006-08-15 06:28:35
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answer #9
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answered by Anonymous
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0* since zero times 2 is still zero.
2006-08-14 16:14:12
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answer #10
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answered by Ell 5
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