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5 answers

Well we have the Ideal Gas Law so lets see...
PV=nRT
P1*V1/T1=P2*V2/T2
Assume isothermic, T1/T2=1
Therefore: P1*V1 / P2*V2=1
P1*V1=P2*V2
In order to get this you must not compress the cylinder. So I guess you can't compress the cylinder. The additional assumption of no heat transfer certainly does not in any way mitigate this law.

2006-08-07 06:10:34 · answer #1 · answered by BRUZER 4 · 0 0

No, this isn't possible. In an adiabatic process V*T^α=constant (α comes from the number of degrees of freedom). Meaning that if you change the volume (compress the gas in your case) the temperature has to change.

2006-08-07 03:22:48 · answer #2 · answered by Sander O 2 · 0 0

well ... I am not 100% sure but I think this is possible ... with total respect to previous answers but I think the rules they used are for all gases ... the question is about Ideal gases ... so If we applied the rule PV=NRT ... Isothermaly that means constant T .. so we can compress ( dec. V ) but we have to increase P ...

2006-08-07 08:31:09 · answer #3 · answered by ferikiko87 1 · 0 0

no it is not possible because when we compress ideal gas it becomes warm especially piston is adiabatic.

2006-08-07 00:27:18 · answer #4 · answered by eshaghi_2006 3 · 0 0

it is possible but only if the prossess should carried out exteremly slow

2006-08-10 19:43:50 · answer #5 · answered by saurabh pareek 2 · 0 0

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