that is working there is Mexican, is it considered Mexican food?
2006-07-27 19:34:56 · 20 answers · asked by FastEddie 5 in Food & Drink ➔ Ethnic Cuisine
No, it's still crap American take away, but I think it does mean McDonalds is exploiting Mexicans
2006-07-27 19:39:40 · answer #1 · answered by clarence 3 · 2⤊ 0⤋
WOW.... Now our fearless leader President Bush has allowed swet shops in America. and of all places McDonalds. But yet you go to Taco bell and there are no mexicans working there.
2006-07-28 03:04:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Nope...but the people there would be considered Mexicans! haha, good ol Mexicans........oh man. I'm not racist I swear! haha, boy I need sleep. I live next to some Mexicans.....ok I don't.....but wouldn't that be nifty....them and their cool music! haha! Ok, I take all that back. hmmm, McDonald's sounds good! Gimme some now!!!
hahahaha! Just read your subject.....Ethnic Cuisine....you rock my friend, you rock!!!! teeeheeeheeee
2006-07-28 02:40:01 · answer #3 · answered by Scoot 4 · 0⤊ 0⤋
No, the workers are part of your community, earning a living and work there so you can have something to eat at McDonalds when you come in to order.
2006-07-28 11:34:06 · answer #4 · answered by Lynda 7 · 0⤊ 0⤋
Not unless it's a mexican that's eating it!
2006-07-28 02:39:21 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Joey120, how the **** is he being racist. Most mexicans work in all fastfood/regular restaurants. And get paid poorly.
2006-07-28 05:13:55 · answer #6 · answered by french_dude4u 3 · 0⤊ 0⤋
no, its still considered Mcdonalds and that is fast food
2006-07-28 02:40:08 · answer #7 · answered by Diana G 2 · 0⤊ 0⤋
Get a life! And stop with all the racist garbage.
2006-07-28 02:38:38 · answer #8 · answered by Joey's Back 6 · 0⤊ 0⤋
nope, mexican is better
2006-07-28 02:38:32 · answer #9 · answered by Coxie Megan 4 · 0⤊ 0⤋
If you go to KFC and all the chicken are spring chicken....do you think you are in spring season?
2006-07-28 06:15:22 · answer #10 · answered by waterdancer 4 · 0⤊ 0⤋