2006-07-01 15:58:07 · 20 answers · asked by Faun 2 in Science & Mathematics ➔ Engineering
Power is measured in Watts, and has the formula of P=I * E, where I = current, and E = voltage. A burned out bulb has no path for the current, so the current = 0. Anything times zero equals zero, right? So no power is used when the bulb is burned out.
2006-07-01 16:06:35 · answer #1 · answered by Anonymous · 1⤊ 1⤋
Actually it is possible for a burned-out incandescent bulb to use electricity if it's turned on. First, the filament supports are insulative, but nothing is perfect insulator, so some current can be carried. Second, in most countries the electric power is AC, and the bulb will have some capacitance that can draw current. Both of these currents would be extremely small, so for all practical purposes, a burned out incandescent does not use electricity.
2006-07-01 16:10:10 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
In addition to ballasts it can use electricity if the fixture has electronics or transformers eg noise/motion/light activated, electronic dimmer or say transformer losses for low voltage lamps. If anypart of the system is still warm then it would indicate some use of electricity although the bulb is burned out
2006-07-01 17:40:59 · answer #3 · answered by wvl 3 · 0⤊ 0⤋
It depend on the type of light fixture. If the bulb is supplied from a ballast (such as fluorescent, HID, mercury vapor, and etc), the ballast will continue to draw power even though the bulb is burned out. Otherwise the answer is No.
2006-07-01 16:10:27 · answer #4 · answered by Wizard 1 · 0⤊ 0⤋
Nope. The only part that uses the electricity is the bulb. The rest is merely a conduit.
2006-07-01 16:00:41 · answer #5 · answered by PermDude 4 · 0⤊ 0⤋
Electricity is the flow of electrical power or charge.
The key word is "flow".
If the filament in your bulb is burnt out, then there is no current (electricity) “flow”.
The electrons are just sitting there reading a book or something.
By the way, I like the color of your hair.
2006-07-01 16:34:00 · answer #6 · answered by Scot G 2 · 0⤊ 0⤋
No it's not. It's an open circuit. You can't have lineloss because the current isn't flowing through the wire. If you touch it, you'll use some electricity because your body has resistance. The kight lights up and uses power because it has resistance. IR=V
2006-07-01 16:05:34 · answer #7 · answered by jayjay5844 2 · 0⤊ 0⤋
Who did paintings on your walls and left huge holes the position the gentle change plate might want to pass? The timber wasn't lengthy sufficient? If the gap the position the gentle change plate might want to in good structure is more desirable than a mild change conceal, you've to improvise. that could entail making your own. likely get a skinny sheet of plywood and paint or beautify it notwithstanding you want, reducing a hollow for the gentle change toggle.
2016-11-30 03:10:31 · answer #8 · answered by sargeant 3 · 0⤊ 0⤋
No. The light bulb is part of the circuit, but if it's blown, there's no circuit, thus no electricity.
2006-07-01 16:00:43 · answer #9 · answered by Ѕємι~Мαđ ŠçїєŋŧιѕТ 6 · 0⤊ 0⤋
no the burned out element opens the circuit just as turning off the switch would
2006-07-01 16:02:07 · answer #10 · answered by oldhippypaul 6 · 0⤊ 0⤋