and his room mate wants to date you would it be ok to do this or should I say no? I like this person hes very nice but I dont want to cause any trouble??
2006-07-01 04:10:00 · 11 answers · asked by amulz1234 3 in Family & Relationships ➔ Singles & Dating
I don't know but read my question that says help you might need to think about it twice!
2006-07-01 04:15:09 · answer #1 · answered by Anonymous · 7⤊ 6⤋
no don't do that because that will cause alot of trouble picture this you and your boyfriend broke up and he started messing with your room mate how would feel
2006-07-01 04:15:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You broke up with the bf for 2 months right? You're a free agent honey, date whomever you want and don't worry about the old bf. chances are he's not worrying about you.
2006-07-01 04:14:19 · answer #3 · answered by Sassy OLD Broad 7 · 0⤊ 0⤋
I say go for it, he will either get over it or he won't. My personal experience with this is: I met my fiance because he was friends with my ex-boyfriend, their not friends now I'm guessing because of me but all is well...you never know what can happen.
2006-07-01 04:15:26 · answer #4 · answered by farmergyrl23 4 · 0⤊ 0⤋
If you like this guy then there is no harm in dating him. Your ex shouldn't mind it. Enjoy!
2006-07-01 04:15:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Go for it, you're single now. You can date anyone you want to.
2006-07-01 04:16:16 · answer #6 · answered by meetha 4 · 0⤊ 0⤋
ya go ahead and date him ur ex will get over it
2006-07-01 04:12:47 · answer #7 · answered by Anonymous · 0⤊ 0⤋
ur ex will get over it and u should go out with his roommate
2006-07-01 04:22:02 · answer #8 · answered by boyfriend41minute 1 · 0⤊ 0⤋
just go for if he likes u i mean
2006-07-01 04:16:30 · answer #9 · answered by Amanda 2 · 0⤊ 0⤋
I say do it. If your x gets jealous, who cares.
2006-07-01 04:15:51 · answer #10 · answered by Kevin 2 · 0⤊ 0⤋
Hell yea you should do it you never know he might be the one for you.
2006-07-01 04:15:05 · answer #11 · answered by jason s 1 · 0⤊ 0⤋