I mean park not drive. Road Tax is obviously needed, but what I want to know is if the car also needs insurance if it is just parked on the road and not being driven.
2007-12-31 07:54:02 · 8 answers · asked by si senor 1 in Cars & Transportation ➔ Insurance & Registration
So for example, if a car has been perfectly legal, ie has MOT, tax, insurance and is road worthy etc... the insurance then runs out and someone is unable to renew it for whatever reason, the car needs to be moved off road?
2007-12-31 08:11:38 · update #1
Tax, insurance and MOT. Otherwise park off road and declare it SORN.
2007-12-31 07:57:33 · answer #1 · answered by Sal*UK 7 · 2⤊ 0⤋
Get the insurance renewed before they tow your car away. My mams neighbour wanted to use her drive because his otherwise roadworthy car wasn't insured. She politely declined, he got new insurance and parks it on the road now.
If you don't want to renew the insurance, park it on someone's private property (with their permission)
2007-12-31 16:30:01 · answer #2 · answered by Linda K 4 · 1⤊ 0⤋
The other answers are mainly correct but bear in mind that after lighting up time you will need external lights on if the speed limit on the road is more than 30 mph, white to the front and red to rear .
2007-12-31 16:08:10 · answer #3 · answered by TATRAFAN 5 · 4⤊ 0⤋
If you're using the road in any way at all with your car, be it driven or parked, you require all the same documentation.
2007-12-31 16:03:49 · answer #4 · answered by Anonymous · 2⤊ 0⤋
Only tax is needed for a car to be parked on the road. To drive it you need tax, mot and insurance.
2007-12-31 16:03:02 · answer #5 · answered by funchop 3 · 0⤊ 6⤋
Road Tax, Third Party Insurance and MOT. It must be in a road legal condition i.e. with wheels etc. and not in a dangerous state with protrusions or bodywork etc.
2007-12-31 16:02:04 · answer #6 · answered by Don't ask, I'm confused 4 · 4⤊ 0⤋
You need insurance and tax and MOT. Once you are on a public road, it doesn't matter that you are not driving it.
2007-12-31 16:01:44 · answer #7 · answered by justanotherguy 4 · 3⤊ 0⤋
No1 answer is perfectly correct,
2007-12-31 15:59:09 · answer #8 · answered by Anthony M 4 · 2⤊ 0⤋