does a bullet fired up land with the same force as when it left the firearm?

Answer 1

If it went straight up it will fall with the force of gravity, 32ft per second squared. This will be much less than the muzzle velocity which would determine foot pounds of force on impact (depends on the caliber and the amount of powder in the load).

Answer 2

They will decelerate on the way up and accelerate on the way down, so in an airless environment, the force would be exactly equal. But the friction with the air reduces the speed more overall, so there is some reduction in force..but it will still kill someone. In places where folks celebrate by firing weapons into the air, fatalities from the falling bullets are not uncommon. It was actually a plot element in The Mexican, I believe - they guy he goes to pick up on a holiday ends up dead from a falling bullet through the top of the skull.

Answer 3

I totally saw this on mythbusters like two nights ago, but the force of a bullet falling back to the ground is called terminal velocity, which is the the rate as which an objects weight and gravity equalizes (or something like that, I wasn't paying as close attention to that episode as I was with the truck and tailgate one). I believe when they shot a .35 mm bullet it was about a little over 100 miles an hour coming back down due to gravity and wind resistance, a bullet leaves a chamber faster then that.

Answer 4

no if fired straight up it gos up, slows due to gravity & air friction ,STOPS then comes back down with the same force as a bullet dropped from from whatever high't it stopped at,
in actual tests bullets fired exactly verticaly (90 degrees) from standard 30 cal military rifles always came back down base first apparently still stabilized & spinning from the spin imposed by the rifleing in the barrel it was fired from.
from a practical stand point its not uncommon for roofers in citys to find bullets in gutter traps that have fell on roofs & been washed off by rain.
a bullet fired from 50 degrees up from the horizontal can still retain enough velocity when it strikes to be deadly depending on bullet weight &ballistic coefficient. at steeper angles they slow too much from air friction by the time they return to ground level to do much damage. this does not apply to heavy shells as even a bowling ball dropped from 20 feet will smash you flat. with its inertia it doesnt need much velocity.

Answer 5

Eventually the bullet reaches terminal velocity and starts coming down. Also generally the heavy end lands first, meaning it lands base first.

Answer 6

It loses the force and becomes weak after traveling certain distance, so it won't land with the same initial force.

Answer 7

No. Once it is coming down the force stablizes because of the weight of the bullet and the pressure of the air against it as it falls. I think that is called terminal velocity.

Answer 8

No, because air resistance slows it on the way up,
so it doesn't retain all it's potential energy,
and resists its acelleration, (slows it), on the way down,
so it doesn't regain all the potential it retained on the way up.

This does NOT mean it can't come down hard enough
to cause serious injury.
It can. - People have been injured, some killed, in this way.

Answer 9

from an ideal standpoint, yes. it will have the same energy behind it as when it left the gun. realistically, no because the air resistance acts more on it as it tumbles down as to when it spun upwards. however, it still lands with enough force to kill someone.

Answer 10

No, it does not.

Otherwise it would come crashing down with a loud bang similar to the one that it escaped the firearm with.