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7 answers

i think it's called the clapper..........

2007-12-28 04:48:22 · answer #1 · answered by Ron B 5 · 2 0

Not that I am aware of. Either way, it takes a switch to turn on/off a light. Be it a mechanical or electronic switch, it still has to be a switch.

One could mount the switch in the fixture or by the outlet either way. I have installed a motion switch on on a wall switch plate and the lights will come on automatically when someone enters a room. Without any movement, the lights will automatically go off after a set amount of time.

good luck.

2007-12-28 04:51:25 · answer #2 · answered by Fordman 7 · 0 0

Motion controlled light fixture or light fixture controlled by cadmium sulfide photoswitch.

2007-12-28 12:56:55 · answer #3 · answered by Anonymous · 0 0

No- you nevertheless ought to rewire it and out it interior the wall- the sensor is rather on the wall the place the swap is going. we've that and it grow to be $$$$ even even though it got here with the fan. i individually could return the fan and purchase yet another with a pull chain- at a mild keep. they have a extra suitable selection. i offered a much less costly battery operated sensor mild that comes on once you stroll into the room to get a some mild so i would be sure to tutor on the fan. good success.

2016-11-25 22:48:59 · answer #4 · answered by Anonymous · 0 0

Somewhere there has to be a switch to turn it on. It could be a PIR (motion sensor switch) or an X10 (powerline remote) or photosensor. Each has a switch.

2007-12-28 06:36:19 · answer #5 · answered by Rich Z 7 · 0 0

Check out X10 home automation products. I have bought a remote controlled relay that plugs into your wall, in which the light plugs into....

2007-12-28 04:57:38 · answer #6 · answered by miner man 2 · 0 0

You can purchase X10 products individually, but if I were starting out I would consider this package at this link:

http://www.x10.com/promotions/ur74a_homerem_1008.html

Have fun - I'm sure you will be hooked on this site.

2007-12-28 05:14:03 · answer #7 · answered by David S 2 · 0 0

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