1 line contain course, 3 others don't .. and then 1 line yes 3 others no. for example:
line 1. MECH665
line 2. (none)
line 3. (none)
line 4. (none)
line 5. MECH751
line 6. (none)
line 7. (none)
line 8. (none)
line 9. MECH746
etc ....
line 2189. URPL699
How many courses is there?
2007-12-27 22:14:38 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The First Who gives the right answer, will be the best answerer !
2007-12-27 22:15:52 · update #1
You have a course listed followed by 3 blank lines. That's one course every 4 lines. If you added 3 blank lines to the end you'd be on line 2192. Divide this by 4 to get 548 courses.
Double-check:
548 courses = 548 lines
547 x 3 blank lines = 1641 lines
Adding together 548+1641 = 2189 as the last line.
2007-12-27 22:20:59 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
Starting at one, for every four lines there is one course. The course comes first and then it is followed by three lines.
2189 / 4 = 547 with remainder of 1.
So the remainder of 1 will be the next course in the next four lines.
Answer: 547 + 1 = 548 courses.
2007-12-27 22:53:05 · answer #2 · answered by Sparks 6 · 0⤊ 0⤋