English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

a survey in a certain locality reveals that the probability of a man dying after the age of 0.6 and the probability of a woman dying after the age of 60 is 0.5. if a couple comes from this locality, what is the probability that:

a) both will die before the age of 60?

b) either will die after 60?

2007-12-27 18:56:40 · 3 answers · asked by stelzii 1 in Science & Mathematics Mathematics

3 answers

PROBLEM A:

P(man dies before 60) = 1 - 0.6 = 0.4
P(woman dies before 60) = 1 - 0.5 = 0.5

P(both die before 60) = 0.4 x 0.5 = 0.2 = 20%

PROBLEM B:

Either will die after 60 is the opposite of both dying before 60.

P(either (or both) die after 60) = 1 - P(both die before 60)
= 1 - 0.20 = 0.80 = 80%

2007-12-27 19:03:05 · answer #1 · answered by Puzzling 7 · 1 0

1

Let M be the event that a male dies before age 60
Let F be the event that a female dies before age 60

P(M) = 1 -0.6 = 0.4
P(F) = 1 - 0.5 = 0.5

Assuming that the events M and F are independent then we simply need to multiply the individual probabilities to find the intersection

P( M ∩ F ) = P(M) * P(F) = 0.4 * 0.5 = 0.2

---- ---- ---- -----

2
For any two events A and B

P(A U B) = P(A) + P(B) - P(A ∩ B)

if we let A be the event the male dies after age 60
Let B be the event that the female dies after age 60, then

P(A U B) = 0.6 + 0.5 - 0.6 * 0.5 = 0.8

2007-12-28 11:50:46 · answer #2 · answered by Merlyn 7 · 0 0

qa
1/5

qb
1/2

2007-12-28 06:13:21 · answer #3 · answered by Mugen is Strong 7 · 0 1

fedest.com, questions and answers