This one has a twist.
Some values in the range will give an absolute value smaller than that which comes from the limit of the domain.
When x = 4 you have the smallest range.
When x = -3 you have the largest range.
so the function gives
g(4) = 0
g(-3) = 7
so the range is 0 <= g() < 7
It is "less than or equal to" only because the minimum value has a domain that is not at the limit.
2007-12-27 18:38:03
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answer #1
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answered by J C 5
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When x = -3, g =7; but since -3
When x approaches 6, g approaches 2;
When x=4, g=0
g cannot be negative
The range of g is 0 <= g < 7
2007-12-28 02:24:19
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answer #2
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answered by pico t 2
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simple your given a function g in terms of x, and a range of values of x. substitute the maximum and minimum values in for x to get the range for the function g.
for x = -3; g(-3) = |4- -3| = 7
for x = 6; g(6) = |4- 6| = 10
thus the range of g is 7<=g<=10, if the domian is -3
cheers
2007-12-28 02:16:38
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answer #3
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answered by skibz26 4
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g(x) = | 4-x |
find the range of g if its domain is -3
I 4-6 I = I -2 I = 2
I 4 - (-3) I = I 4 + 3 I = 7
The range is 2 < g(x) < 7 ANS
teddy boy
2007-12-28 02:16:59
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answer #4
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answered by teddy boy 6
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minimum value=l 4-4 l=l 0 l=0
max value=l 4-(-3) l=l 7 l=7
hence,range of g(x) is 0
2007-12-28 02:22:10
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answer #5
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answered by William 3
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The range is g is greater than or equal to zero. It's vertex is at x=4 being the lowest point of the function.
2007-12-28 02:15:13
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answer #6
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answered by Jeremy D 3
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[0,7) becoz min value occurs when u put x=4 and max value when x=-6...
2007-12-28 02:28:36
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answer #7
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answered by divya jain 2
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