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2007-12-27 16:01:34 · 11 answers · asked by sm.prasadd 1 in Science & Mathematics Mathematics

11 answers

There are five possibilities.
4H
3H 1T
2H 2T
1H 3T
4T

What exactly you want to know. Pls rephrase the question

2007-12-27 16:09:58 · answer #1 · answered by Anonymous · 0 1

While it is true that if you flipped a coin 4 times, heads should come up four twice and tails twice, you would not expect this to always happen. For example, if you flipped that coin one hundred times, on average you would expect that it would be 50heads and 50tails but sometimes you would get 51heads and 49tails, 52tails and 48heads and so on. So in reality, it should be 2 heads and tails, but it could be any combinations. Heres the breakdown:

2 heads and 2 tails: 37.5%
3 heads and 1 tail: 25%
3 tails and 1 head: 25%
0 tails and 4 heads: 6.25%
0 heads and 1 tail: 6.25%

All combos add up to 100% so that is the correct breakdown.

2007-12-27 18:11:10 · answer #2 · answered by pickupman546237 1 · 0 0

Assuming Mutually Exclusive Odds:

First time = 1/2 chance of being heads or tails
Second-Fourth time = same probability of being heads or tails

So you flip it 4 times and it doesn't matter if I flipped it 100 times. If the outcome is mutually exclusive I would have expected half of the flips to be heads and half to be tails.

So, the theoretical answer is 2 heads and 2 tails.

2007-12-27 16:06:37 · answer #3 · answered by TM 3 · 0 1

all =16 chances
1 head=4chances=1/4
2 head =6 chance=3/8
3 heads=4chances=1/4
4 heads =1 chance=1/16
4 tails=1 chance=1/16

2007-12-27 16:33:32 · answer #4 · answered by someone else 7 · 0 0

there is a 1/16 chance you will get four heads
there is a 1/16 chance you will get four tails
there is a 1/4 chance of getting three heads and one tail
there is a 1/4 chance of getting three tails and one head
there is a 3/8 chance of getting two heads and two tails

the way to calculate these probabilities is by the binomial distribution:

P(n)=N!/n!(N-n)! *p^n*q^(N-n)

where: P(n) is the probability of n events occuring;
N is the total number of trials
p is the probability that the event occurs
q is the probability that the event does not occur

2007-12-27 16:12:05 · answer #5 · answered by kuiperbelt2003 7 · 1 1

statistically 2 heads and two tails. You can never predict the result of a toss though, its always 50/50

2007-12-27 16:05:24 · answer #6 · answered by Bumblebee 4 · 0 1

50/50 chance for Heads or Tails each time.

2007-12-27 16:05:03 · answer #7 · answered by Professor Snugglesworth 4 · 0 1

are you pertaining to the probability you could get a head or a tail? ofcourse it's 50:50. 50% that you'll get a head and 50% that you'll get a tail.

2007-12-27 16:05:39 · answer #8 · answered by Meeko 1 · 0 1

There are a number of possibilities.

Was this a serious question? If so, you really need to rephrase it.

2007-12-27 16:07:12 · answer #9 · answered by Curt Monash 7 · 0 1

theoretically, the head shows up twice or the tail also so shows up twice

2007-12-27 16:06:10 · answer #10 · answered by Anonymous · 0 1

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