Polynomial division is difficult to show and explain in this forum, as such I will point you to a few sites:
A couple good references on how to do polynomial division are:
http://www.purplemath.com/modules/polydiv.htm
http://campus.northpark.edu/math/PreCalculus/Algebraic/Polynomial/Factoring/index.html
here are two links to polynomial division calculators:
http://library.wolfram.com/webMathematica/Education/LongDivide.jsp
http://calc101.com/webMathematica/long-divide.jsp
I'm not going to note a solution as it is to difficult to know what you are asking without the use of parenthesis to define the groupings of terms are you asking:
(9-x^2) / (10x^2-28x-6)
or
9- (x^2/ 10x^2) -28x -6 = -28x + 2.9
2007-12-27 12:35:41
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answer #1
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answered by Merlyn 7
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9-x^2 / 10x^2-28x-6
(3-x)(3+x) / (10x+2)(x-3)
the 2 x-3 cancel out
3+x/10x+2
2007-12-27 12:09:38
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answer #2
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answered by Dave aka Spider Monkey 7
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(9 -- x^2) / (10x^2 -- 28x -- 6)
= (3 + x)(3 -- x) / 2(x -- 3)(5x + 1)
= -- (x + 3) / 2(5x + 1)
2007-12-27 12:18:51
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answer #3
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answered by sv 7
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I'm really not sure how to do that, but I'll factor the denominator for fun.
10x^2 - 30x + 2x - 6
=5x(2x - 6) + 2x - 6
=(5x + 1)(2x - 6)
2007-12-27 12:44:00
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answer #4
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answered by Anonymous
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top simplifies to
(-x+3)(x+3)
bottom simplifies to
(5x+1)(2x-6)
This gives you
(-x+3)(x+3)/(5x+1)(2x-6)
pull out a neg on the top, and a 2 on the bottom to get
(-1)(x-3)(x+3)/(2)(5x+1)(x-3)
(x-3)'s cancel out, so you get
(-x-3)/(10x+2)
2007-12-27 12:12:31
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answer #5
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answered by Ari R 3
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-x(to the 4th power)/10 -28x+3
2007-12-27 12:11:31
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answer #6
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answered by howifallintoyoureyes 2
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3-X over 2(5x+1)
2007-12-27 12:10:37
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answer #7
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answered by richard s 1
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i think it's
-(x^2-9)/2(5x+1)(x-3)=-(x+3)/2(5x+1)
2007-12-27 12:08:27
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answer #8
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answered by Anonymous
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7x^2/3
2007-12-27 12:07:18
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answer #9
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answered by litleshortarse 1
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You should pay attention in class
2007-12-27 12:06:37
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answer #10
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answered by PupeTTo Loco 2
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