Solve each porportion?

Question

c+3/c-1=c+2/c-3

Answer 1

We can cross-multiply:

(c + 3) times (c - 3) = (c - 1) times (c + 2)

c^2 - 9 = c^2 +2c - c - 2

c^2 - 9 = c^2 +c - 2

Bring everything that's on the left side of the equation to the right side of the equation and equate the whole equation to zero.

c^2 + c - 2 -c^2 + 9 = 0

The positive c^2 and negative -c^2 cancel out.

We now have this:

c - 2 + 9 = 0

c + 7 = 0

c = -7

How do we know that's true?

After we plug -7 for c in the original proportion, we should get the same answer on both sides of the equation.

Let's see if we are right?

Ready?

You were given:

c+3/c-1=c+2/c-3

Let c = -7

That means everywhere you see the letter c, replace it with -7 and simplify.

(-7) + 3/(-7) - 1 = (-7) + 2/(-7) - 3

-4/-8 = -5/-10

1/2 = 1/2...It checks!!!

We got the same answer of 1/2 on both sides of the equation.

See it?

That's how we know that c = -7 is the right answer.

Answer 2

cross-multiplying
(c+3)(c -3) = (c-1)(c+2)
c^2 - 9 = c^2 + c - 2
subtract out the c^2 terms

-9 = c - 2
-7 = c

Answer 3

well first you must find the least common denominator (LCD)
In this case, the LCD is: (c-3)(c-1)
So multiply each side by:
(c-3)(c-1)

Do some canceling out and then u get:
(c-3)(c+3)=(c+2)(c-1) which reduces to
c^2-9=c^2+c-2 The c^2's cancel and you get:
-9=c-2 Solve and you get:
c=-7

Answer 4

c+3/c-1=c+2/c-3

c^2-9= c^2+c-2

c^2-9+2=c^2-c^2+c-2+2

c=-7

Answer 5

(c+3)(c-3)=(c+2)(c-1)
c^2-9=c^2+c-2
c^2-c^2-c=-2+9
-c=7
c=-7

Answer 6

um...
cross multiply
c+3*c-3=
c^2-3c+3c-9=c^2-9
c-1*c+2=c^2+2c-1c-2=c^2+c-2
c^2+c-2=C^2-9
+9 +9
--------------------------
c^2+c+7=c^2
-c^2 -c^2
--------------------------
c+7=0
-7 -7
-----------------
c= -7


that is ur answer