sixty-four cubes of the same size are used to form a larger cube. the outside of the new cube is sprayed with sparkles. how many of the smaller cubes will not have any sparkles on them?
please show the work.
thanks.
2007-12-27 10:32:53 · 6 answers · asked by bballdud123 2 in Science & Mathematics ➔ Mathematics
To use 64 cubes, each edge would have 4 and each side 16. The inner cubes would only be 2x2x2 = 8 cubes without sparkles.
that's it! :)
2007-12-27 10:38:14 · answer #1 · answered by Marley K 7 · 0⤊ 0⤋
The larger cube is 4*4*4 = 64 small cubes.
Going across, the two outer cubes have sprarkles, but the two inner ones don't.
Going down, same.
Going the third direction, same.
The small cubes with no sparkles = 2*2*2 = 8
2007-12-27 18:40:20 · answer #2 · answered by Steve A 7 · 0⤊ 0⤋
The answer is zero.
Each side of the larger cube contains three rows of smaller cubes that are four cubes in length. Every cube within the larger cube has at least one side that is sprayed with sparkles.
2007-12-27 18:44:28 · answer #3 · answered by C 3 · 0⤊ 0⤋
Given that 64=4^3, the larger cube will be a 4x4x4 cube; therefore the "inner" cube will be a 2x2x2=8 cube. This is the answer.
2007-12-27 18:39:39 · answer #4 · answered by JCS 5 · 0⤊ 0⤋
64^(-3)=4
only the cernter have no sparkles, so the inside cube is 2*2*2=8 small cubes
2007-12-27 18:37:51 · answer #5 · answered by Omega 3 · 0⤊ 0⤋
ur asking the wrong perosn =[ guess lk 4 or something
2007-12-27 18:36:15 · answer #6 · answered by Anonymous · 0⤊ 2⤋