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Change each exponential expression to an equivalent expression involving a logarithm.

(1) 3^x = 4.6

(2) e^(2.2) = M

2007-12-27 10:20:48 · 6 answers · asked by journey 1 in Science & Mathematics Mathematics

6 answers

(1) 3^x = 4.6

x = log base 3 of 4.6

(2) e^(2.2) = M

2.2 = ln M

Remember that a logarithm is an exponent. This means that when you have an expression in exponential form, the exponent is going to be equal to something when you re-write the expression in logarithmic form.

2007-12-27 10:28:39 · answer #1 · answered by math geek 3 · 0 0

To do this, the exponent becomes the coefficient of the log term. For example in the second problem, you can use Natural Logs and have
2.2 ln e = ln M
since ln e = 1, ln M =2.2

2007-12-27 13:20:02 · answer #2 · answered by cattbarf 7 · 0 0

ok so 6 is the backside (abbreviated as 'b'), and six.5 is a extensive sort which I dont understand what to call, even though it is abbreviated as 'M'. it is a normal log expression: Log(base b)M = x. Now in simple terms plug the numbers in: Log(base 6)6.5 = x. And thats the respond =). substantial: once you write this on paper, the backside (b) is written as a subscript.

2016-11-25 20:43:51 · answer #3 · answered by ? 4 · 0 0

log(base 3) 4.6 = x
log(base e) M = 2.2

2007-12-27 10:24:17 · answer #4 · answered by ¿ /\/ 馬 ? 7 · 0 0

1) x = ln4.6 / ln3, since xln3 = ln4.6
2) 2.2 = lnM

2007-12-27 10:23:56 · answer #5 · answered by sahsjing 7 · 0 0

x = ln(4.6) / ln(3)

2.2 = ln(M)

2007-12-27 10:26:06 · answer #6 · answered by MrCouscous 1 · 0 0

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