a season record for the bulldogs baseball team is shown. what percent of games did the bulldogs win?
the won 7 games, loss 5 games and 3 ties
2007-12-27 09:47:18 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Total games played by the Bulldogs is
7 + 5 + 3 =15
Total games won = 7
To find the percentage that they won, divide the total games won by the total games played times 100%, so 7/15 = 0.466 X100% = ~47%
2007-12-27 09:54:23 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋
Win % is basically the number of games won divided by the total games played:
7 + 5 + 3 = 15 games total
Win % = 7 / 15 = 0.4667
They won 46.67% of their games!
2007-12-27 17:54:29 · answer #2 · answered by Mavis 5 · 0⤊ 0⤋
divide the # of games won (7) by the total # of games (7+5+3) so itd be 7/15, which is about 47%
2007-12-27 18:04:14 · answer #3 · answered by Amanda 6 · 0⤊ 0⤋
add them up and put the won over the total game.
7 won + 5 loss + 3 ties = 15
so it, 7/15=.46667=.47
about 47 percent
2007-12-27 17:57:19 · answer #4 · answered by Vu H 4 · 0⤊ 0⤋
the team won 7 out of 15 games, therefore their winning percentage is 46.7%
2007-12-27 17:55:43 · answer #5 · answered by juas003 1 · 0⤊ 0⤋
(7/15)100=700/15=46.67 percent
2007-12-27 17:54:49 · answer #6 · answered by cidyah 7 · 0⤊ 0⤋