Basic Algebra?

Question

How would 7/c - 3/d divided by 4/d be simplified?

Thanks for the help!
10 points for the clearest answer!

Answer 1

Ok, so we have:

(7/c - 3/d)/(4/d)

Well, if we distribute the 4/d, we get:

[(7/c)/(4/d) - (3/d)(4/d)]

Now, when you divide two fractions, you take the top one and multiply it by the reciprocal of the denominator, for example:

(a/b)/(c/d) = (a/b)*(d/c)

So, know we apply that rule to each of the fractions:

(7d/4c) - 3/4

Now, if we create an LCD in the 3/4 by multiplying it by c, we can further simplify it:

(7d/4c) - 3c/4c

(7d - 3c)/4c

And that's as simple as you can get it.

Answer 2

The first answer is right.
Part one ignore 4/d to start with
I want to get the bottom figures the same in this case cd
to do this multiply 7/c by d and 4/d by c
=7d/cd-3c/cd
because they both are divided by cd you can make this
(7d-3c)/cd
bring back the 4/d but because you are dividing make it d/4
(7d-3c)/cd)*d/4
or (7d-3c)*d/4cd this is easy on with pencil and paper
Cancel a d from the top and the bottom
(7d-3c)/4c

Hope it helps.

Answer 3

(7/c - 3/d) / (4/d) = (7/c - 3/d) * (d/4) = 7/c * d/4 - 3/4
= 7/4 *d/c - 3/4

That's as simplified as I can make it. Enjoy!

Answer 4

(7/c - 3/d)/(4/d)

= 7/c * d/4 - 3/d * d/4
= 7d/4c - 3/4

Answer 5

multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
((7)/(c)*(d)/(d)-(3)/(d)*(c)/(c))*(d)/(4)

Complete the multiplication to produce a denominator of cd in each expression.
((7d)/(cd)-(3c)/(cd))*(d)/(4)

Combine the numerators of all expressions that have common denominators.
((7d-3c)/(cd))*(d)/(4)

Multiply the rational expressions to get (d(((7d-3c))/(cd)))/(4).
(d((7d-3c)/(cd)))/(4)

Remove the common factor of d from the numerator of the first expression and denominator of the second expression.
(1)/(4)*(7d-3c)/(c)

Multiply 4 by c to get 4c.
(7d-3c)/(4c)- final answer

Answer 6

(7/c - 3/d)/(4/d)

(7d - 3c)/4c {multiply big numerator and big denominator by cd}

or

7d/4c - 3/4

Answer 7

(7/c -- 3/d) / (4/d)
= (7/c -- 3/d)*d/4
= 7d/4c -- 3/4

Answer 8

(7 / c - 3 / d) / (4 / d)
(7*d / c*d - 3*c / d*c) / (4/d)
((7d - 3c) / cd) / (4/d)
(7d - 3c) / (4/d)*cd
(7d - 3c) / (4c)
(7d / 4c) - (3c / 4c)
(7d / 4c) - (3/4)

Answer 9

7/c - 3/d = (7d - 3c)/ cd
(7d - 3c)/cd * d/4
(7d-3c)/4c

Answer 10

[ (7d - 3c) / (cd) ] / (4 / d)
[ (d) (7d - 3c) ] / (4cd)
(7d - 3c) / (4c)