English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories
2

How for example would you simplify this question?

(a+b)/ (1/c)

The answer is c(a+b) but I was wondering how this is worked out.

Thanks for the help,

10 points to the first reply that answers it best!

2007-12-27 07:51:41 · 10 answers · asked by Simon F 2 in Science & Mathematics Mathematics

10 answers

(a+b)/ (1/c)

Basically, when you divide a fraction, you can also rewrite it by multiplying by its reciprocal, that is, in this case, 1/c reciprocal would be c/1 or c

Thus,
=(a+b)/ (1/c) is also equal to
=(a+b) * c
=c(a+b)

Other examples of reciprocals:
1/4 reciprocal = 4/1 or 4
2/3 reciprocal = 3/2 (basically flip the top with the bottom)
c/d reciprocal = d/c
pi/2 reciprocal = 2/pi ,etc.

2007-12-27 07:56:26 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 1 1

(a + b) / (1/c) = (a + b)*(c/1) = (a + b)c

2007-12-27 08:04:25 · answer #2 · answered by sv 7 · 0 0

(a+b)/ (1/c)
= (a+b)*c/1
= c(a+b)

2007-12-27 13:16:51 · answer #3 · answered by m!l@ 2 · 0 0

First, you have to write it out vertically (meaning that you use a horizontal line and put a & b on the top, and 1/c on the bottom).

It's quite simple, really.
To get rid of the fraction on the bottom, multiply both sections by c (1/c x c (a+b) x c)

And you get: c(a + b)/1
Get rid of the one, and there's your answer.

Hope this made sense.

2007-12-27 07:58:12 · answer #4 · answered by Anonymous · 0 0

Whenever you have the numerator divided by a fraction the rule is to invert(take the reciprocal) of the divisor and multiply thus

(a+b)/(1/c) becomes (a+b)*c

2007-12-27 08:10:38 · answer #5 · answered by justforfun_1811 3 · 0 0

I think to divide you flip the thing you divide by over, so it is c/1 and multiply instead of divide. c/1 will equal c.
so (a+b) x c = c(a+b).

Something like that anyway, apologies to my maths tutor.

2007-12-27 08:00:22 · answer #6 · answered by Anonymous · 0 0

ok
(a+b)/(1/c)
Means that you are dividing a+b by 1/c
That is like doing division twice, which turns it into multiplication(like a negative times a negative)
so you get c(a+b)
Hope this helps

2007-12-27 07:57:18 · answer #7 · answered by Ari R 3 · 0 0

(a+b)/(1/c)
need to remove the denominator

c/1(a+b)/(1/c)*(c/1)=c(a+b)

2007-12-27 07:57:20 · answer #8 · answered by Itsok 3 · 1 0

(a+b)/ (1/c)
(a+b)/1 *c/1
c(a+b)
you have to treat it like a fraction so you turn the second fracton upside down and time them together

2007-12-28 01:02:02 · answer #9 · answered by angel2cool 3 · 0 0

Hi,

The problem is:
(a + b).....1
---------. ÷.--- =
...............c

(a + b).....c
---------. X.--- = (a + b)c
...............1

I hope that helps!! :-)

2007-12-27 07:58:50 · answer #10 · answered by Pi R Squared 7 · 0 0

fedest.com, questions and answers