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Can someone show me how they got their answer? I never had any algebra, and my daughter needs me to help her. HELP

2007-12-27 06:29:52 · 10 answers · asked by mseger68 1 in Science & Mathematics Mathematics

10 answers

Brackets are required:-
(1/6) d + 13 = 20
(1/6) d = 7
d = 42

2007-12-30 05:57:16 · answer #1 · answered by Como 7 · 1 0

Assuming 1/6 d +13 = 20

1/6 d = 7

d = 7x6

d=42

1 divided by 6d +13 = 20 is impossible
1 divided by 6d then +13 = 20 is also impossible

2007-12-27 14:36:05 · answer #2 · answered by Anonymous · 0 0

In algebra when trying to find x (or in this case d) when you start to eliminate things from the problem, what you do to one side you must also do to the other
1/6d + 13 = 20
-13 -13 subtract 13 from both side
_____________
1/6d = 7

1/6 X 6/1(AKA 6) = 1
Leaving 1d (or just d) by itself on the left

because you multiplied the left side of the equation by six you now have to muliply the right side by 6 as well.
7 X 6 = 42

d=42

2007-12-27 14:39:27 · answer #3 · answered by Anonymous · 0 0

Basically you have to isolate the variable and to do that you move the constants to the other side.

1/6d + 13 = 20
1/6d = 20 - 13
1/6d = 7
d = 7 * 6
d = 42

2007-12-27 14:33:28 · answer #4 · answered by Anonymous · 2 0

1/6d + 13 = 20 : subtract 13 from both sides
1/6d = 7 : multiply both sides by 6

d = 42

2007-12-27 14:34:07 · answer #5 · answered by remowlms 7 · 0 0

Well, the answer is 42.

1) subtract 13 on each side so 20-13
2)1/6d=7
3)divide each side with 1/6 so d is by itself
4) answer is d=42

2007-12-27 14:34:33 · answer #6 · answered by Rosie 3 · 0 0

move 13 over so it would be 1/6d=7 and d=42

2007-12-27 14:33:26 · answer #7 · answered by Anonymous · 0 0

Oh, God, you're going to make me think...
1/6d=7...
0.8571428571428571=d.
Thats what I got.

2007-12-27 14:36:17 · answer #8 · answered by Michelle <3 1 · 0 3

don't you turn 1/6 into a decimal, or something like that?

2007-12-27 14:33:45 · answer #9 · answered by Lindsey 3 · 0 2

uhh rightt..
7+13:S

2007-12-27 14:32:24 · answer #10 · answered by wHyDoUcArE 2 · 0 2

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