Avegail needs to determine the distance at certain points across a lake. Her crew and she are able to measure the distances of the triangular lake. Find how wide the lake is to the nearest tenth of a meter.
hypotenuse = 130 meters
length = 60 meters
a. 70 m
b. 8.4 m
c. 143.2 m
d. 115.3 m
2007-12-27 06:09:22 · 7 answers · asked by . 1 in Science & Mathematics ➔ Mathematics
h = hypotenuse
l = length
w = width
h²=l²+w²
(130)²=(60)²+(w)²
w=√13300
w=115.3256259 m
answer is d. 115.3 m
2007-12-27 06:14:20 · answer #1 · answered by Murtaza 6 · 0⤊ 0⤋
width ^2 = 130^2 - 60^2
width = 115.3
2007-12-27 06:13:38 · answer #2 · answered by norman 7 · 0⤊ 0⤋
Use the Pythagorean:
Length² + Width² = Hypotenuse²
60² + Width² = 130²
Width² = 130² - 60²
= 16900 - 3600
You can finish the calculations
2007-12-27 06:16:22 · answer #3 · answered by DWRead 7 · 0⤊ 0⤋
130^2 - 60^2 = 13300 almost = 115.3m
then the answer is 115.3
2007-12-27 06:16:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋
sqrt(130^2 - 60^2) 115.3
2007-12-27 06:36:07 · answer #5 · answered by ikeman32 6 · 0⤊ 0⤋
easy it is sqrt(130*130 - 60*60)
2007-12-27 06:13:21 · answer #6 · answered by gjmb1960 7 · 0⤊ 0⤋
d) 115.3 m
2007-12-27 06:15:37 · answer #7 · answered by jaya 4 · 0⤊ 0⤋