Which of the following could be used to prove triangle TOP is congruent to triangle DEN?

Question

http://i40.photobucket.com/albums/e215/xxs3xp1stolxx/Picture9.png

Answer 1

answer a.

if TOP is congruent DEN
then T corresponds to D
O to E
P to N

there is enough information to calculate the x adn next all angles and sides ( use sine rule for second triangle )

Answer 2

ok! you isn't waiting to coach triangles congruent by employing employing the section-section-perspective once you think approximately that if i furnish you with a triangle with 2 aspects(a and b) and an perspective opposite one in each of them(A or B), there would desire to be 3 circumstances: Case a million: if the dimensions b is smaller than length h (the altitude), then a,b and A won't be able to sort a triangle. for that reason if we do now no longer have those triangle, there's now no longer something to coach! Case 2: if the dimensions b is an comparable as h (the altitude), then they're going to sort a ideal-triangle, so as which you will teach them congruent. Case 3: if the dimensions b is larger than h (the altitude), then there are 2 opportunities. the physique of suggestions C (the physique of suggestions formed by employing a and b) would desire to be obtuse or acute. So we do now no longer have sufficient suggestion to end the degree of the physique of suggestions C, and for that reason we gained't teach that the triangles are congruent.

Answer 3

the top answer is the right one. the reason is by side angle side. i guess you might say its choice A.