2007-12-27 04:22:24 · 6 answers · asked by hpfreak6790 1 in Science & Mathematics ➔ Mathematics
This one turns out quite nicely. First, take the square root of the squared terms and take them out of the square root. Then you can split up the fraction to where the left part and the right part are over sqrt(ab), something will cancel and you will have a pretty simple answer.
2007-12-27 04:30:40 · answer #1 · answered by Drew 3 · 0⤊ 0⤋
divide each term in numerator by sqrt(ab)
sqrt(a^2b)/sqrt(ab) = sqrt a [since the b's cancel, a^2/a = a]
sqrt(ab^2) /sqrt(ab) = sqrt b
answer: sqrt a + sqrt b
2007-12-27 12:30:47 · answer #2 · answered by Linda K 5 · 1⤊ 1⤋
sqrt a^2b + sqrt ab^2 divided by sqrt ab =
[â(a²b)+ â(ab²)] / â(ab) = ( aâb + bâa)/ â(ab) · â(ab)/â(ab) =
(abâa+abâb)/ (ab) = âa + âb
saludos.
2007-12-27 12:32:34 · answer #3 · answered by lou h 7 · 0⤊ 0⤋
Again, your question is ambiguous and should have parentheses for clarity. I'm assuming you mean
                    [â(a²b) + â(ab²)]/â(ab)
which you can easily solve if you apply the rules from my previous answer.
http://answers.yahoo.com/question/index;_ylt=Akfm32HOZVQV52p76N5aocPty6IX;_ylv=3?qid=20071227090113AAU6idj&show=7#profile-info-XlRsjA8raa
2007-12-27 12:30:47 · answer #4 · answered by DWRead 7 · 2⤊ 0⤋
[sqrt(a^2b) + sqrt(ab^2)]/sqrt(ab)
sqrt(a^2b)/sqrt(ab) + sqrt(ab^2)/sqrt(ab)
sqrt(ab)sqrt(a)/sqrt(ab) + sqrt(ab)sqrt(b)/sqrt(ab)
sqrt(a) + sqrt(b)
2007-12-27 12:35:46 · answer #5 · answered by kindricko 7 · 0⤊ 0⤋
=(a sqrt(b) + b sqrt(a))/ sqrt(ab)
= sqrt(a) + sqrt(b)
2007-12-27 12:31:43 · answer #6 · answered by norman 7 · 0⤊ 0⤋