( 8 + √ 6 ) / √ 2
(√ 2) ( 8 + √ 6 ) / 2
( 8 √ 2 + √ 12 ) / 2
( 8 √ 2 + 2 √ 3 ) / 2
4 √ 2 + √ 3
2007-12-29 21:46:17
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answer #1
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answered by Como 7
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rationalizing denominators. - To simplify the cálculs he|she|it agrees on reducing the denominator in rational d 'a fraction
When the denominator is a monomial, like the one that asks for us l 'exercise, the two terms of the fraccioneria amount are multiplied by the denominator:
(8 + √6)/√2 = √2 (8 + √6)/(√2)(√2) = [8√2 + (√2)(√6)] /√4= (8√2 +√12)/2 =
8√2 +[√(2²)(3)] /2 = (8√2 +2√3)/2 = 2(4√2 +√ 3)/2 = 4√2 +√3
= 7,388905057
Waiting that knowledgeable s'agi, he|she|it receives a
greeting from Catalonia and until the next one
2007-12-27 11:15:26
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answer #2
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answered by josep d 7
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Your question is ambiguous. Do you mean
(8 + √6)/√2
or
8 + (√6/√2)
----------------------------------------
When it comes to evaluating square roots, remember
a) The radicand (that's the quantity under the square root sign) can be factored and evaluated in parts. For example,
√18 = √(9·2)
= √9·√2
= 3√2
b) Don't leave a square root in the denominator. An answer like "1/√2" will lose points. To remove the √2 from the denominator, multiply the fraction by √2/√2:
(1/√2) · (√2/√2) = (1·√2)/(√2·√2)
= √2/2
2007-12-27 04:23:08
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answer #3
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answered by DWRead 7
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[8 + sqrt(6)]/sqrt(2)
8/sqrt(2) + sqrt(2)sqrt(3)/sqrt(2)
8/sqrt(2) + sqrt(3)
8sqrt(2)/2 + sqrt(3)
4sqrt(2) + sqrt(3)
2007-12-27 04:08:09
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answer #4
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answered by Anonymous
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OK
8 + sqrt6 / sqrt2
Remeber order of operations
8 + (sqrt6/sqrt2)
8 + (sqrt3*sqrt2/sqrt2)
8 + (sqrt3)
8 + 1.732
9.732
Hope that helps.
2007-12-27 04:17:39
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answer #5
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answered by pyz01 7
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8sqrt2+sqrt12 divided by two
simplify to
sprt3+4sqrt2
2007-12-27 04:05:53
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answer #6
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answered by The Answer 3
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9.732050808
2007-12-27 04:05:51
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answer #7
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answered by Kenneth Koh 5
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7.389
2007-12-27 04:05:35
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answer #8
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answered by numbr1TXfan 4
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3⤋