tan x (2sin x - 1) = - (2 sin x - 1)
tan x (2sin x - 1) + (2sin x - 1) = 0
(2 sin x - 1)(tan x + 1) = 0
sin x = 1 / 2 , tan x = - 1
x = 30 ° , 150° , 135° , 315°
or
x = π / 6 , 5π / 6 , 3π / 4 , 7π / 4
2007-12-23 19:39:17
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answer #1
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answered by Como 7
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2sinxtanx - tanx = 1 - 2sinx
tanx (2sinx - 1) = -2sinx + 1
tanx (2sinx - 1) = -(2sinx - 1) << Equation 1
From here, we have 2 cases.
Case 1
> 2sinx - 1 = 0 << Equation 2
If 2sinx - 1 = 0, then we cannot divide Equation 1 by 2sinx - 1, as doing so would mean dividing by 0, which would give an undefined answer. It is a common mistake of many to divide immediately by a common factor without taking into consideration the possibility of it being 0.
Instead, we can find the value of x from Equation 2.
2sinx - 1 = 0
2sinx = 1
sinx = 1/2
There are 2 values of x for which sinx = 1/2, namely, 30 and 150.
Case 2
> 2sinx - 1 is not equal to 0
Accordingly, we can divide Equation 1 by 2sinx - 1 since it is not equal to 0.
[tanx (2sinx - 1) = -(2sinx - 1)] / (2sinx - 1)
tanx = -1
x = 135 and 315
Thus, the possible values of x are 30, 150, 135 and 315
2007-12-23 18:36:08
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answer #2
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answered by sparx 2
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2sin x tan x - tan x= 1-2sin x
tan x (2 sin x - 1) = 1- 2 sin x
- tan x (1- 2 sinx ) = 1- 2 sinx
-tan x = 1
tan x = -1
x = -45 or 135 or these values + multiples of 360
2007-12-23 18:28:55
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answer #3
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answered by PeterT 5
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2sin x tan x - tan x= 1-2sin x
=> tanx (2sinx-1) =1-2sinx
( - 1) tanx (1-2sinx) = 1-2sinx
tanx =-1
x = -45 degrees or 360 -45 =315 degrees
2007-12-23 18:38:02
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answer #4
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answered by Roslyn** luv maths 2
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To solve trig equations, start by putting all the parts in terms of sin and cos.
It looks like common denominators would help with this problem
2 sinx * sinx sinx
----------------- - ----------- = 1 - 2sinx
cosx cosx
2 sin^2(x) - sinx = cosx (1 - 2sinx)
sinx (2 sinx - 1) = cosx (-1) (2sinx - cosx)
sinx/cosx = -1
tanx = -1
... okay, now I need a calculator ... but this should give you the answer.
Remember: the same rules apply to sinx and cosx as to x and y when you are solving them.
If it makes it easier, redefine your problem as follows:
sinx = a
conx = b
tanx = sinx/cosx = a/b
so your question is really:
2a * a/b - a/b = 1 - 2a
(simplify as I did above)
a/b = -1
Have fun and keep practicing. Just write out all your steps and be careful with your algebra rules
2007-12-23 18:30:30
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answer #5
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answered by Sarah M 2
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2sin x tan x - tan x= 1-2sin x
=> 2sin x tan x - tan x - 1 + 2sin x = 0
=> 2sin x (tan x + 1) - 1(tan x + 1) = 0
=> (2sin x - 1) (tanx + 1) = 0
=> sin x = 1/2 or tan x = - 1
=> sin x = sin (π/6) or tan x = tan ( -π/4)
=> x = kπ + (-1)^k (π/6) or x = kπ - π/4, k ∈ Z.
2007-12-23 18:32:51
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answer #6
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answered by Madhukar 7
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2sinxtanx -- tanx = 1 -- 2sinx
Or (2sinx -- 1)(tanx + 1) = 0
giving sinx = 1/2 = sin 30 deg hence x = 30 deg, 150deg,
and tanx = -- 1 = tan 135 deg, hence x = 135 deg, 225 deg,
2007-12-23 20:09:54
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answer #7
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answered by sv 7
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tanx = -1
x is 135 or 315 degrees ( +360 as many times)
2007-12-23 18:23:36
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answer #8
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answered by BOND 3
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