The determinant of the matrix?

Question

(1-c^2........ 2-c), is:
(1+c............1)

a)1-c b)-1-c c)c-1 d)c+1

Answer 1

(1-c²) - (1+c)(2-c)
= (1+c)(1-c) - (1+c)(2-c)

simplified... -1-c

§

Answer 2

-1-c

Answer 3

the determinant of a matrix A = (a*d) - (b*c) where
A = { a b }
.......{ c d }
so we have:
a = 1-c²
b = 2-c
c = 1+c
d = 1

((1-c²) * 1) - ((2-c) * (1+c)) = 1-c² - (2+c-c²)
= 1 - c² - 2 - c + c² = -1 - c

the answer is b

*edit
oh and by the way I see all your homework problems out in the mathematics forum, you should really do your own homework and learn this stuff cause it's not hard

Answer 4

(a...b)
(c...d)

Determinant = (ad-bc)

( (1-c²)(1) )-( (2-c)(1+c) )
(1-c²) - ( 2-c -c²)
-1 -c

Answer is B) -1 - c

Answer 5

It's 1-c² -(2+c-c²) = -1-c.
In general the determinant of
a b
c d
is ad - bc.