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(b 2), is invertible if:
(-b a)

a) a is not equal to 2 b) b is not equal to 2 c) a = 2 d) b=2

2007-12-23 16:59:51 · 4 answers · asked by tony2007 2 in Science & Mathematics Mathematics

4 answers

A matrix is invertible if it's determinant is non-zero. The determinant of:

b 2
-b a

is b*a - (-b*2) = b*a +2b

This is non-0 when a is not equal to -2. None of the multiple choice answers are correct. Was choice (a) typed correctly ?

2007-12-23 17:09:06 · answer #1 · answered by MartinWeiss 6 · 0 0

A matrix can be inverted if its determinant is non zero. The determinant of the matrix you post is:

ab +2b = b(a+2), the value of this determinant is zero if either b is zero or a=-2, could your choice a) be a is not equal to minus 2?

2007-12-23 17:28:30 · answer #2 · answered by kuiperbelt2003 7 · 0 0

| b 2|
|-b a| is invertible if ∆ ≠ 0

∆ = ab + 2b = b(a+2) ≠ 0

if b ≠ 0

a +2 ≠ 0 => a ≠ - 2

2007-12-23 17:28:54 · answer #3 · answered by piano 7 · 0 0

The matrix A is invertible if det(A) is not 0.
Here det A = ab + 2b = b(a+2).
So all your choices are correct here.

2007-12-24 14:24:59 · answer #4 · answered by steiner1745 7 · 0 0

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