This is regarding fractions
2007-12-23 15:38:59 · 3 answers · asked by tekpek 1 in Education & Reference ➔ Homework Help
12y-84....factor it, 12(y-7)
y^2-3y-28, factor it....(y-7)(y+4) cancel out teh y-7's
12/y+4
4y-24...4(y-6)
y^2-2y-24 (y-6)(y+4) cancel out y-6's
4/y+4
12/y+4 divided by 4/y+4....take recip of 2nd and mulitply
12/y+4 * y+4/4....cancel out y+4's....and you ahve 12/4....reduce and you ahve 3
2007-12-23 15:45:41 · answer #1 · answered by csd 3 · 0⤊ 0⤋
12y-84/ y^2-3y-28 / 4y-24/ y^2-2y-24
12(y-7)/ (y-7)(y+4) / 4(y-6)/ (y-6)(y+4)
12(y-7).(y-7) (y+4)* (y-6)(y+4)/ 4(y-6)
the 2 y-7' y+4 and y-6 cancel the 12 is 3 and the 4 is 1
answer is 3
2007-12-24 04:56:16 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
i would have to say use a calculator but thats jsut me or jsut dont do it.
2007-12-23 15:44:01 · answer #3 · answered by webbington 3 · 0⤊ 1⤋