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2007-12-23 15:22:36 · 2 answers · asked by ReignInVictory 2 in Science & Mathematics Chemistry

2 answers

C2H6 weighs:

(2 x 12.01) + (6 x 1.01) = 30.08g/mole

The wt % carbon is just the weight of the carbon divided by the total formula weight:

100% x [(2 x 12.01)/30.08g] = 79.85%

If you need grams of carbon in the 0.198g sample it would be:

0.7985 x 0.198g = 0.158g of carbon.

2007-12-23 15:37:19 · answer #1 · answered by Flying Dragon 7 · 0 0

calculate the percentage of carbon present

12.01(2) + 1.008(8) = 24.02 + 8.064 = 32.084 g/mol

% carbon 32.084/24.02 = 75% of carbon and 25% hydrogen

75% X 0.198g = 0.1485 g

2007-12-23 15:36:56 · answer #2 · answered by chemica1031 3 · 0 1

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