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I have a T/F question which says, "Justify your answer. For all positive real numbers x, log(x) > 0

How would I go about finding "all" instances of this, or is it generally assumed that finding *any* single instance of proof/disproof is enough? I already know that if x=1 this statement is false. Log(1) = 0 and 0 is not > 0. Is that enough?

I'm studying this alone in my own free time so any additional advice for studying this type of math is appreciated.

2007-12-23 14:54:28 · 5 answers · asked by Matt S 2 in Science & Mathematics Mathematics

5 answers

Hi,

You are correct that this is false. One contradiction like log(1) = 0 is sufficient to prove it is not always true. For what it is worth, realize that the log of any number between 0 and 1 is a negative value.

log (1/100) = log(1/10²) = log(10^(-2)) = -2

I hope that helps!! :-)

2007-12-23 15:03:37 · answer #1 · answered by Pi R Squared 7 · 0 0

General principle: One counterexample to a
statement is enough to prove it false.
So log(1) = 0 disproves the statement.

2007-12-24 10:34:10 · answer #2 · answered by steiner1745 7 · 0 0

You got it, Matt. That is "disproof by example". Keep up the good work and keep posting questions here if you have a problem.

2007-12-23 23:13:26 · answer #3 · answered by cattbarf 7 · 0 0

You're correct. To prove it false you only have to give one counterexample and using x=1 is a particularly obvious one.

2007-12-23 22:59:48 · answer #4 · answered by MartinWeiss 6 · 0 0

so.. itll be false.. for all positive real numbers GREATER THAN 1, log (x) > 0

2007-12-23 22:59:10 · answer #5 · answered by Anonymous · 0 0

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