Can you show them apart so that I know which is which. I appreciate it soooo much!
First one is:
(r-5s+4) + (8r+4s) +(s+7)
Second one is:
(x to the fourth - 12x to the second +35) Divided by (x to the second - 7)
THANK YOU!!
2007-12-23 12:43:35 · 9 answers · asked by Tank 2 in Science & Mathematics ➔ Mathematics
[07](r-5s+4)+(8r+4s)+(s+7)
=r-5s+4+8r+4s+s+7
=r+8r-5s+4s+s+4+7
=9r+11
(x^4-12x^2+35)/(x^2-7)
x^4-12x^2+35
Substituting x^2 by a and hence x^4 by a^2,the expression becomes
a^2-12a+35
=(a-7)(a-5)
=(x^2-7)(x^2-5) [putting back the value of a]
Therefore,
(x^4-12x^2+35)/(x^2-7)
=(x^2-7)(x^2-5)/(x^2-7)
=x^2-5
2007-12-23 12:52:30 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
(r -- 5s + 4) + (8r + 4s) + (s + 7)
= r -- 5s + 4 + 8r + 4s + s + 7
= 9r + 11
(x to the fourth -- 12x to the second + 35) divided by (x to the second -- 7)
= (x^4 -- 12x^2 + 35) / (x^2 -- 7)
= (x^4 -- 7x^2 -- 5x^2 + 35) / (x^2 -- 7)
= {x^2(x^2 -- 7) -- 5(x^2 -- 7)} / (x^2 -- 7)
= (x^2 -- 7)(x^2 -- 5) / (x^2 - 7)
= x^2 -- 5
2007-12-23 12:58:34 · answer #2 · answered by sv 7 · 0⤊ 0⤋
I don't get what you mean but anyway, for the first one just collect like terms...
(r-5s+4) + (8r+4s) +(s+7)
=9r+11
The second one is hard... urgh...
(x^4 - 12x^2 + 35)/(x^2 - 7)
You have to factor the top of the division thingy so that one of the multiplying thingies is equal to x^2 - 7 so that they cancel out... Let's factor...
x^4 - 7x^2 - 5x^2 + 35
=x^2(x^2 - 7) - 5(x^2 - 7)
=(x^2 - 5)(x^s - 7)
Soo...
(x^2 - 5)(x^s - 7)/(x^2 - 7) = x^2 - 5 <-- cancel each other out..
2007-12-23 13:11:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
First one: Simply collect like terms
(r-5s+4)+(8r+4s)+(s+7)
r-5s+4+8r+4s+s+7
r+8r -5s+4s+s +4+7
9r+11
Second one: Factor
(x^4-12x^2+35)/(x^2-7)
(x^2-7)(x^2-5) / (x^2-7)
(x^2-5)
If it helped to clarify the technique for factoring a bit
better for you,
Let x^2=u
Then the problem becomes (u^2-12u+35)/(u-7)
(u-7)(u-5)/(u-7)
=(u-5)
Nor replace u with x^2
=(x^2-5)
2007-12-23 13:03:05 · answer #4 · answered by Grampedo 7 · 0⤊ 0⤋
= (r - 5s + 4) + (8r + 4s) + (s + 7)
= r - 5s + 4 + 8r + 4s + s + 7
= 9r + 11
You could divide directly here without the nitty-gritty substitution:
= (x^4 - 12x^2 + 35)/(x^2 - 7)
= x^2 - 5
2007-12-23 13:28:27 · answer #5 · answered by Jun Agruda 7 · 3⤊ 1⤋
(r-5s+4) + (8r+4s) +(s+7)
Remove brackets:
r-5s+4 + 8r+4s +s+7
Gather like terms:
r+8r -5s+4s +s +4+7
Simplify:
9r+0s+11
Make equation:
9r = -11
r = -11/9
2007-12-23 13:48:07 · answer #6 · answered by Robert S 7 · 0⤊ 0⤋
would if I could remember how to do it...sorry been awhile man.....
2007-12-23 12:52:36 · answer #7 · answered by Anonymous · 0⤊ 0⤋
what???
im going to have nightmares!!!
2007-12-23 12:48:11 · answer #8 · answered by ashley 3 · 0⤊ 0⤋
what the ****?
2007-12-23 12:51:53 · answer #9 · answered by Anonymous · 0⤊ 0⤋