Calculate the enthalpy change?

Question

Consider the combustion of 1.56 mol of liquid
ethanol (C[2]H[5]OH) to gaseous water and car-
bon dioxide. Calculate the enthalpy change
for this reaction. The pertinent enthalpies of
formation (in kJ/mol) are
Hf H2O = -241.8
Hf CO2 = -393.5
Hf C[2]H[5]OH = -277.7
Answer in units of kJ.

Answer 1

3O2 + C2H5OH -> 2CO2 + 3H2O

Enthalpy of reaction
= 277.7 +2x(-393.5) + 3x(-241.8)
= /kJ

I will let you do the honor of obtaining the ans

Answer 2

Cobrasha is using {products} - {reactants} to calculate change per mole.

You need to multiply that by number of moles to get the answer to your Q.