solve x^2-4x-32=0?

1 ⤊

2007-12-23 06:48:56 · 4 answers · asked by blue_eyed_woman_23 3 in Science & Mathematics ➔ Mathematics

(x-8)(x+4)=0
therefore x=8 and x= -4

2007-12-23 06:52:12 · answer #1 · answered by nicknameyo 3 · 1⤊ 0⤋

(x+4)(x-8)=0
x=-4 x=8
because -4 +4=0 x 8-8=0 0x0=0

also -8x4=-32
if you multiply (x+4)(x-8) you will get the original equation

2007-12-23 14:55:12 · answer #2 · answered by the worr e ore 5 · 0⤊ 0⤋

(x - 8)(x + 4) = 0
x = 8 , x = - 4

2007-12-25 05:07:09 · answer #3 · answered by Como 7 · 0⤊ 0⤋

(x+4)(x-8)=0....
so...x= -4,8

2007-12-23 14:52:34 · answer #4 · answered by Gracieღ™ 3 · 0⤊ 0⤋