2007-12-23 06:48:10 · 4 answers · asked by blue_eyed_woman_23 3 in Science & Mathematics ➔ Mathematics
(x-1)² = 6
If we notice|fix in it is|treats about the square of the difference of two numbers
(x-1)² we see that him and aixó him equal to:
The square of the difference of two numbers him equal to|in the
square of the first, less the double of the first for the second, more
the square of the second. Therefore we have:
x² -2 x +1² = 6
equaling zero the equation:
to
x²-2x+1-6=0
x² -2 x -5 = 0
resolving|solving:
x' = 3,44948 ; x"= -1,44948
Waiting that knowledgeable s'agi, he|she|it receives a
salutament and even the next one.
Good Christmas
2007-12-23 12:41:07 · answer #1 · answered by josep d 7 · 1⤊ 0⤋
(x - 1) = 屉6
x = 1 ± â6
2007-12-25 05:08:50 · answer #2 · answered by Como 7 · 0⤊ 0⤋
x-1=+-sqrt 6
x= 1+sqrt 6 or 1-sqrt 6
2007-12-23 14:58:07 · answer #3 · answered by mwanahamisi 3 · 0⤊ 0⤋
(x-1)^2=6
x^2 + 1=6
x^2=5
x=Square root of 5
2007-12-23 14:57:15 · answer #4 · answered by Chantol๛ ดวงอาทิตย์๛ 4 · 0⤊ 0⤋